Example
The cast iron cylinder and head of a pump are attached by a number of M16x2 class 8.8 bolts. How many bolts are required to resist a pressure load of 200 kN on the head ? A design factor of 2 is appropriate.
First find component stiffnesses to relate the bolt load to the external load via ( 3a).
- Bolt
- The threaded length is not given, but from the sketch the runout coincides with the joint faces - though this exposed thread length is really excessive. Take half head and nut lengths to be 0.5 x 0.8 x 16 = 7 mm.
Shank length = 20+7 = 27 mm area = π/4 x 162 = 201 mm2 Thread length = 24+7 = 31 mm area = As = 157 mm2 ( Table 1 ) 1/kb = Σ L/AE = ( 27/201 + 31/157 )/207 kb = 624 kN/mm . . . watch units ! - Flange
- Assume lengths of effective conical frusta are each (20+24)/2 = 22 mm to equalise reactive areas as shown, and that ( 4) is applicable to cast iron with little error. So, for one frustum
kf = 100 x 16 ( 0.702 + 0.654 x 16/22) / ( 1 - 0.12 x 16/22) = 2065 kN/mm So, for the two flange frusta in series 1/kj = 2 ( 1/2065 ) kf = 1030 kN/mm
The equivalent stiffness is therefore 1/ke = 1/624 + 1/1030 ; ke = 389 kN/mm
The proof load of the bolts is Fp = As Sp = 157 x 590 = 93 kN Assuming that the bolts are tightened initially to three-quarters of their proof load, Fi = 0.75 x 93 = 70 kN So applying ( 3a) with a design factor of 2 on the external load, to 'z' bolts presumably equally loaded : Fb = 70 + 2 x 200 x 389 / 1030 z and ≤ Fp = 93 kN from which z ≥ 6.3
Either 8 bolts would be used (7 are difficult to make equidistant) or 6 bolts might be employed with preload reduced to 73% rather than 75% of proof. But we have seen that it is impossible to expect 2% accuracy - so select 6 bolts. This decision is bolstered by the knowledge that since the joint is self-energising, a high preload is unnecessary from a joint operational point of view.
The example has demonstrated how to apply the theory, however the problem refers to the 'cylinder' and 'head' of a pump so presumably the pump is reciprocating and the loading on this joint will be alternating, therefore a fatigue rather than a static analysis would have been much more appropriate. We consider bolt fatigue in the next section.
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